http://poj.org/problem?id=2299
给出n个数,每次只能交换两个相邻的数,问使得n个数有序最少需要交换多少次。
归并排序的模板,重在理解,小白书p144.
#include <stdio.h> #include <map> #include <set> #include <stack> #include <queue> #include <vector> #include <cmath> #include <stdio.h> #include <stdlib.h> #include <cstring> #include <iostream> #include <limits.h> #include <algorithm> #define LL long long #define _LL __int64 using namespace std; const int maxn = 500010; LL cnt; int n,a[maxn],t[maxn]; void merge_sort(int *a, int x, int y, int *t) { if(y-x > 1) { int m = x + (y-x)/2; int p = x,q = m,i = x; merge_sort(a,x,m,t); merge_sort(a,m,y,t); while(p < m || q < y) { if(q >= y || (p < m && a[p] <= a[q])) t[i++] = a[p++]; else { t[i++] = a[q++]; cnt += m-p; } } for(i = x; i < y; i++) a[i] = t[i]; } } int main() { while(~scanf("%d",&n)&&n) { for(int i = 0; i < n; i++) scanf("%d",&a[i]); cnt = 0; merge_sort(a,0,n,t); printf("%lld\n",cnt); } return 0; }
http://acm.hdu.edu.cn/showproblem.php?pid=4911
每次只能交换两个相邻的数,最多交换K次,问最后的最少的逆序对数是多少
#include <stdio.h> #include <map> #include <set> #include <stack> #include <queue> #include <vector> #include <cmath> #include <stdio.h> #include <stdlib.h> #include <cstring> #include <iostream> #include <limits.h> #include <algorithm> #define LL long long #define _LL __int64 using namespace std; const int maxn = 500010; _LL cnt,k; int n,a[maxn],t[maxn]; void merge_sort(int *a, int x, int y, int *t) { if(y-x > 1) { int m = x + (y-x)/2; int p = x,q = m,i = x; merge_sort(a,x,m,t); merge_sort(a,m,y,t); while(p < m || q < y) { if(q >= y || (p < m && a[p] <= a[q])) t[i++] = a[p++]; else { t[i++] = a[q++]; cnt += m-p; } } for(i = x; i < y; i++) a[i] = t[i]; } } int main() { while(~scanf("%d %I64d",&n,&k)) { for(int i = 0; i < n; i++) scanf("%d",&a[i]); cnt = 0; merge_sort(a,0,n,t); if(k >= cnt) printf("0\n"); else printf("%I64d\n",cnt-k); } return 0; }
原文地址:http://blog.csdn.net/u013081425/article/details/38395413