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Invert a binary tree.
1 1
/ \ / 2 3 => 3 2
/ 4 4
1 /** 2 * Definition of TreeNode: 3 * public class TreeNode { 4 * public int val; 5 * public TreeNode left, right; 6 * public TreeNode(int val) { 7 * this.val = val; 8 * this.left = this.right = null; 9 * } 10 * } 11 */ 12 public class Solution { 13 /** 14 * @param root: a TreeNode, the root of the binary tree 15 * @return: nothing 16 */ 17 public void invertBinaryTree(TreeNode root) { 18 // write your code here 19 if (root == null) return; 20 21 TreeNode left = root.left; 22 root.left = root.right; 23 root.right = left; 24 25 invertBinaryTree(root.left); 26 invertBinaryTree(root.right); 27 } 28 }
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原文地址:http://www.cnblogs.com/beiyeqingteng/p/5657461.html