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Given two array of integers(the first array is array A, the second array is arrayB), now we are going to find a element in array A which is A[i], and another element in array B which is B[j], so that the difference between A[i] and B[j] (|A[i] - B[j]|) is as small as possible, return their smallest difference.
For example, given array A = [3,6,7,4], B = [2,8,9,3], return 0。
分析：
首先sort, 然后用两个指针分别指向两个array的头部，谁小移动谁。
1 public class Solution { 2 /** 3 * @param A, B: Two integer arrays. 4 * @return: Their smallest difference. 5 */ 6 public int smallestDifference(int[] A, int[] B) { 7 Arrays.sort(A); 8 Arrays.sort(B); 9 10 int pa = 0; 11 int pb = 0; 12 13 int diff = Integer.MAX_VALUE; 14 15 while (pa < A.length && pb < B.length) { 16 if (A[pa] < B[pb]) { 17 diff = Math.min(diff, Math.abs(A[pa] - B[pb])); 18 pa++; 19 } else if (A[pa] == B[pb]) { 20 return 0; 21 } else { 22 diff = Math.min(diff, Math.abs(A[pa] - B[pb])); 23 pb++; 24 } 25 } 26 return diff; 27 } 28 }
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原文地址：http://www.cnblogs.com/beiyeqingteng/p/5657480.html
