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Codeforces Round #360 (Div. 2) D. Remainders Game(中国剩余定理)

时间:2016-07-10 23:21:19      阅读:202      评论:0      收藏:0      [点我收藏+]

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D. Remainders Game

Today Pari and Arya are playing a game called Remainders.

Pari chooses two positive integer x and k, and tells Arya k but not x. Arya have to find the value 技术分享. There are n ancient numbers c1, c2, ..., cn and Pari has to tell Arya 技术分享 if Arya wants. Given k and the ancient values, tell us if Arya has a winning strategy independent of value of x or not. Formally, is it true that Arya can understand the value 技术分享 for any positive integer x?

Note, that 技术分享 means the remainder of x after dividing it by y.

Input

The first line of the input contains two integers n and k (1 ≤ n,  k ≤ 1 000 000) — the number of ancient integers and value k that is chosen by Pari.

The second line contains n integers c1, c2, ..., cn (1 ≤ ci ≤ 1 000 000).

Output

Print "Yes" (without quotes) if Arya has a winning strategy independent of value of x, or "No" (without quotes) otherwise.

Examples
input
4 5
2 3 5 12
output
Yes
input
2 7
2 3
output
No
Note

In the first sample, Arya can understand 技术分享 because 5 is one of the ancient numbers.

In the second sample, Arya can‘t be sure what 技术分享 is. For example 1 and 7 have the same remainders after dividing by 2 and 3, but they differ in remainders after dividing by 7.

#include <cstdio>
#include <cmath>
#include <cstring>
#include <algorithm>
#include <map>
#include <iostream>
using namespace std;
#define ll long long
ll lcm;
const int maxn = 1e6 + 10;
ll getlcm(ll a, ll b) {
    return a / __gcd(a, b) * b;
}

ll p[maxn];

int main() {
    ll n, k;
    while(~scanf("%I64d %I64d", &n, &k)) {
        for(int i = 1; i <= n; i++) scanf("%I64d", &p[i]);
        ll lcm = 1;
        int flag = 0;
        for(int i = 1; i <= n; i++) {
            lcm = getlcm(lcm, p[i]);
            lcm = lcm % k;
            if(lcm == 0) {
                puts("Yes");
                flag = 1;
                break;
            }
        }
        if(!flag) puts("No");
    }
}

 

Codeforces Round #360 (Div. 2) D. Remainders Game(中国剩余定理)

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原文地址:http://www.cnblogs.com/lonewanderer/p/5658581.html

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