码迷,mamicode.com
首页 > 其他好文 > 详细

HDU 4920 Matrix multiplication 矩阵相乘。稀疏矩阵

时间:2014-08-06 17:53:01      阅读:206      评论:0      收藏:0      [点我收藏+]

标签:des   style   blog   http   color   java   os   io   

Matrix multiplication

Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 1775    Accepted Submission(s): 796


Problem Description
Given two matrices A and B of size n×n, find the product of them.

bobo hates big integers. So you are only asked to find the result modulo 3.
 

 

Input
The input consists of several tests. For each tests:

The first line contains n (1≤n≤800). Each of the following n lines contain n integers -- the description of the matrix A. The j-th integer in the i-th line equals Aij. The next n lines describe the matrix B in similar format (0≤Aij,Bij≤109).
 

 

Output
For each tests:

Print n lines. Each of them contain n integers -- the matrix A×B in similar format.
 

 

Sample Input
1
0
1
2
0 1
2 3
4 5
6 7
 

 

Sample Output
0
0 1
2 1
 
Author
Xiaoxu Guo (ftiasch)
 

 

Source
 

 

Recommend
We have carefully selected several similar problems for you:  4919 4918 4917 4916 4915 
 
 1 #include<iostream>
 2 #include<stdio.h>
 3 #include<cstring>
 4 #include<cstdlib>
 5 using namespace std;
 6 
 7 struct Matrix
 8 {
 9     int mat[801][801];
10 }hxl,tom,now;
11 void solve(int n)
12 {
13     int i,j,k;
14     for(i=1;i<=n;i++)
15     {
16         for(k=1;k<=n;k++)
17         {
18             if(hxl.mat[i][k]==0) continue;
19             for(j=1;j<=n;j++)
20             {
21                 now.mat[i][j] = now.mat[i][j] + hxl.mat[i][k]*tom.mat[k][j];
22             }
23         }
24     }
25     for(i=1;i<=n;i++)
26     {
27         for(j=1;j<=n;j++)
28         {
29             if(j==1)printf("%d",now.mat[i][j]%3);
30             else printf(" %d",now.mat[i][j]%3);
31         }
32         printf("\n");
33     }
34 }
35 int main()
36 {
37     int n;
38     int i,j;
39     while(scanf("%d",&n)>0)
40     {
41         for(i=1;i<=n;i++)
42             for(j=1;j<=n;j++)
43             {
44                 scanf("%d",&hxl.mat[i][j]);
45                 hxl.mat[i][j]%=3;
46                 now.mat[i][j] = 0;
47             }
48         for(i=1;i<=n;i++)
49             for(j=1;j<=n;j++)
50             {
51                 scanf("%d",&tom.mat[i][j]);
52                 tom.mat[i][j]%=3;
53             }
54         solve(n);
55 
56     }
57     return 0;
58 }

 

HDU 4920 Matrix multiplication 矩阵相乘。稀疏矩阵,布布扣,bubuko.com

HDU 4920 Matrix multiplication 矩阵相乘。稀疏矩阵

标签:des   style   blog   http   color   java   os   io   

原文地址:http://www.cnblogs.com/tom987690183/p/3894742.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!