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ACM--类Fibonacci 数列--HDOJ 1021--Fibonacci Again--水

时间:2016-07-13 16:43:58      阅读:129      评论:0      收藏:0      [点我收藏+]

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HDOJ 题目地址:传送门


Fibonacci Again

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 51982    Accepted Submission(s): 24582


Problem Description
There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2).
 

Input
Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000).
 

Output
Print the word "yes" if 3 divide evenly into F(n).

Print the word "no" if not.
 

Sample Input
0 1 2 3 4 5
 

Sample Output
no no yes no no no

题意:Fil数列,第一做的时候用递归,结果超内存,后来测试结果发现数据大一点就卡到不行,后来打了一个表,然后就过了


#include<stdio.h>
#include<iostream>
using namespace std;
int result[1000001];
int main(){
    int n;
    result[0]=7%3;
   result[1]=11%3;
   for(int i=2;i<1000001;i++){
      result[i]=(result[i-1]+result[i-2])%3;
   }
    while(scanf("%d",&n)!=EOF){
        if(result[n]){
             printf("no\n");
        }else{
         printf("yes\n");

        }

    }
}



ACM--类Fibonacci 数列--HDOJ 1021--Fibonacci Again--水

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原文地址:http://blog.csdn.net/qq_26891045/article/details/51888815

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