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public class LatLonUtil { private static double PI = 3.14159265; private static double EARTH_RADIUS = 6378137; private static double RAD = Math.PI / 180.0; /// <summary> /// 根据提供的经度和纬度、以及半径,取得此半径内的最大最小经纬度 /// </summary> /// <param name="lat">纬度</param> /// <param name="lon">经度</param> /// <param name="raidus">半径(米)</param> /// <returns></returns> public static double[] GetAround(double lat, double lon, int raidus) { Double latitude = lat; Double longitude = lon; Double degree = (24901 * 1609) / 360.0; double raidusMile = raidus; Double dpmLat = 1 / degree; Double radiusLat = dpmLat * raidusMile; Double minLat = latitude - radiusLat; Double maxLat = latitude + radiusLat; Double mpdLng = degree * Math.Cos(latitude * (PI / 180)); Double dpmLng = 1 / mpdLng; Double radiusLng = dpmLng * raidusMile; Double minLng = longitude - radiusLng; Double maxLng = longitude + radiusLng; return new double[] { minLat, minLng, maxLat, maxLng }; } /// <summary> /// 根据提供的两个经纬度计算距离(米) /// </summary> /// <param name="lng1">经度1</param> /// <param name="lat1">纬度1</param> /// <param name="lng2">经度2</param> /// <param name="lat2">纬度2</param> /// <returns></returns> public static double GetDistance(double lng1, double lat1, double lng2, double lat2) { double radLat1 = lat1 * RAD; double radLat2 = lat2 * RAD; double a = radLat1 - radLat2; double b = (lng1 - lng2) * RAD; double s = 2 * Math.Asin(Math.Sqrt(Math.Pow(Math.Sin(a / 2), 2) + Math.Cos(radLat1) * Math.Cos(radLat2) * Math.Pow(Math.Sin(b / 2), 2))); s = s * EARTH_RADIUS; s = Math.Round(s * 10000) / 10000; return s; } }
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原文地址:http://www.cnblogs.com/xinzheng/p/5667364.html