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Given a non-empty binary search tree and a target value, find the value in the BST that is closest to the target.
Note:
Analysis:
Find the two values before and after the target. Use two integer to record the most recent two values.
Solution:
1 /** 2 * Definition for a binary tree node. 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */ 10 public class Solution { 11 public class Pair { 12 int val1; 13 int val2; 14 15 Pair(int v1, int v2) { 16 val1 = v1; 17 val2 = v2; 18 } 19 } 20 21 public boolean closestValueRecur(TreeNode curNode, double target, Pair res) { 22 if (curNode == null) 23 return false; 24 25 if (closestValueRecur(curNode.left, target, res)) 26 return true; 27 res.val1 = res.val2; 28 res.val2 = curNode.val; 29 if (res.val1 <= target && res.val2 >= target) 30 return true; 31 if (closestValueRecur(curNode.right, target, res)) 32 return true; 33 34 return false; 35 } 36 37 public int closestValue(TreeNode root, double target) { 38 Pair res = new Pair(Integer.MIN_VALUE, Integer.MIN_VALUE); 39 40 closestValueRecur(root, target, res); 41 42 if (res.val1 == Integer.MIN_VALUE) 43 return res.val2; 44 if (res.val2 <= target) 45 return res.val2; 46 47 if (target - res.val1 < res.val2 - target) 48 return res.val1; 49 else 50 return res.val2; 51 } 52 }
LeetCode-Closest Binary Search Tree Value
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原文地址:http://www.cnblogs.com/lishiblog/p/5667153.html