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Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match, such that there is a bijection between a letter in pattern and a non-empty word in str. Examples: pattern = "abba", str = "dog cat cat dog" should return true. pattern = "abba", str = "dog cat cat fish" should return false. pattern = "aaaa", str = "dog cat cat dog" should return false. pattern = "abba", str = "dog dog dog dog" should return false. Notes: You may assume pattern contains only lowercase letters, and str contains lowercase letters separated by a single space.
public class Solution { public boolean wordPattern(String pattern, String str) { //boolean followPattern=true; if(pattern == null || pattern.length() == 0){ return false; } String[] strArray=str.split(" "); if(strArray.length != pattern.length()){ return false; } Map<Character, String> patternMap=new HashMap<Character, String>(); for(int i=0; i<pattern.length(); i++){ char c=pattern.charAt(i); if(patternMap.containsKey(c)){ String value=patternMap.get(c); if(!value.equals(strArray[i])){ return false; } } else{ for(Character ca : patternMap.keySet()){ if(patternMap.get(ca).equals(strArray[i])){ return false; } } patternMap.put(c, strArray[i]); } } return true; } }
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原文地址:http://www.cnblogs.com/incrediblechangshuo/p/5671852.html