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/* * 372. Super Pow * 2016-7-16 by Mingyang */ private int mod = 1337; public int superPow(int a, int[] b) { int n = b.length; int ans = 1; for (int i = n - 1; i >= 0; i--) { ans = ans * quick_pow(a, b[i]) % mod; a = quick_pow(a, 10); } return ans; } int quick_pow(int a, int b) { int ans = 1; a %= mod; while (b > 0) { if ((b & 1) !=0) ans = ans * a % mod; a = a * a % mod; b >>= 1; } return ans; }
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原文地址:http://www.cnblogs.com/zmyvszk/p/5677732.html