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Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in any order.
public class Solution { public int[] intersection(int[] nums1, int[] nums2) { int l1=nums1.length; int l2=nums2.length; Set<Integer> set=new HashSet<Integer>(); for(int i=0; i<l1; i++){ set.add(nums1[i]); } Set<Integer> resSet=new HashSet<Integer>(); for(int i=0; i<l2; i++){ if(set.contains(nums2[i])){ resSet.add(nums2[i]); } } int[] a=new int[resSet.size()]; /* for(int i=0; i<resSet.size(); i++){ a[i]=resSet.get(i); } */ int i=0; for(int j : resSet){ a[i]=j; i++; } return a; } }
LeetCode-Intersection of Two Arrays
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原文地址：http://www.cnblogs.com/incrediblechangshuo/p/5683316.html
