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LeetCode-Guess Number Higher or Lower

时间:2016-07-19 23:41:21      阅读:201      评论:0      收藏:0      [点我收藏+]

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We are playing the Guess Game. The game is as follows:

I pick a number from 1 to n. You have to guess which number I picked.

Every time you guess wrong, I‘ll tell you whether the number is higher or lower.

You call a pre-defined API guess(int num) which returns 3 possible results (-1, 1, or 0):

-1 : My number is lower
 1 : My number is higher
 0 : Congrats! You got it!
Example:
n = 10, I pick 6.

Return 6.

 

 

/* The guess API is defined in the parent class GuessGame.
   @param num, your guess
   @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
      int guess(int num); */

public class Solution extends GuessGame {
    public int guessNumber(int n) {
        int l=1;
        int r=n;
        while(l<=r){
            int m=l+((r-l)/2);
            if(guess(m) == 1){
                l=m+1;
            }
            else if(guess(m) == -1){
                r=m-1;
            }
            else{
                return m;
            }
        }
        return -1;
    }
}

 

LeetCode-Guess Number Higher or Lower

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原文地址:http://www.cnblogs.com/incrediblechangshuo/p/5686600.html

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