POJ 2993 Emag eht htiw Em Pleh 模拟

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 using namespace std;
 5 char q[10],w[100];
 6 char e[10],r[100];
 7 char white[12]= {‘K‘,‘Q‘,‘R‘,‘B‘,‘N‘,‘P‘};
 8 char black[12]= {‘k‘,‘q‘,‘r‘,‘b‘,‘n‘,‘p‘};
 9 char map1[18][35];
10 int s1,s2;
11 int main()
12 {
13     int i,j;
14     for(i=1; i<=17; i++)                    
15         for(j=1; j<=33; j++)
16         {
17             if(i%2==1&&j%4==1)
18                 map1[i][j]=‘+‘;
19             else  if(i%2==1)
20                 map1[i][j]=‘-‘;
21             else  if(i%2==0&&j%4==1)
22                 map1[i][j]=‘|‘;
23             else if(i%4==2&&(double)(j%8)/4<=1&&j%8!=0)
24                 map1[i][j]=‘.‘;
25             else if(i%4==0&&((double)(j%8)/4>1||j%8==0))
26                 map1[i][j]=‘.‘;
27             else
28                 map1[i][j]=‘:‘;
29         }
30     for(int k=1; k<=2; k++)        
31     {
32         scanf("%s%s",q,w);
33         s1=strlen(w);
34         if(q[0]==‘W‘)
35         {
36             for(i=0; i<=5; i++)
37                 for(j=0; j<=s1; j++)
38                 {
39                     if(w[j]==white[i])
40                         map1[2*(9-w[j+2]+‘0‘)][4*(w[j+1]-‘a‘)+3]=white[i];
41                     if(w[j]==‘,‘&&w[j+1]>96)
42                         map1[2*(9-w[j+2]+‘0‘)][4*(w[j+1]-‘a‘)+3]=‘P‘;
43                 }
44         }
45         if(q[0]==‘B‘)
46         {
47             for(i=0; i<=5; i++)
48                 for(j=0; j<=s1; j++)
49                 {
50                     if(w[j]==white[i])
51                         map1[2*(9-w[j+2]+‘0‘)][4*(w[j+1]-‘a‘)+3]=black[i];
52                     if(w[j]==‘,‘&&w[j+1]>96)
53                         map1[2*(9-w[j+2]+‘0‘)][4*(w[j+1]-‘a‘)+3]=‘p‘;
54                 }
55         }
56     }
57     for(i=1; i<=17; i++)
58     {
59         for(j=1; j<=33; j++)
60             cout<<map1[i][j];
61         cout<<endl;
62     }
63     return 0;
64 }