标签:des style blog http color os io for
Say you have an array for which the ith element is the price of a given stock on day i.
Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).
算法思路:
计算出每个增区间的差值。求总和。
1 public class Solution { 2 public int maxProfit(int[] prices) { 3 if(prices == null || prices.length < 2) return 0; 4 int pre = 0, post = 1,length = prices.length; 5 int buy = 0,profit = 0; 6 for(int i = 0; i < prices.length; i++,pre = i - 1, post = i + 1){ 7 if(post < length && prices[pre] >= prices[i] && prices[post] > prices[i]){ 8 buy = prices[i]; 9 } 10 if( prices[i] > prices[pre] && (post != length ? prices[i] >= prices[post] : true) ){ 11 profit += prices[i] - buy; 12 } 13 } 14 return profit; 15 } 16 }
[leetcode]Best Time to Buy and Sell Stock II,布布扣,bubuko.com
[leetcode]Best Time to Buy and Sell Stock II
标签:des style blog http color os io for
原文地址:http://www.cnblogs.com/huntfor/p/3895969.html