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推荐博客:http://blog.csdn.net/metalseed/article/details/8039326
接下来是,对应的线段树的题目解析。
hdu 1166 排兵布阵(构造线段树,单点更新,查询区间和)
1 #include <cstdio> 2 #include <cstring> 3 typedef long long LL; 4 LL sum[50000 << 2]; 5 #define lson l,m,rt << 1 6 #define rson m+1,r,rt << 1 | 1 7 void pushup(int rt){sum[rt] = sum[rt << 1] + sum[rt << 1 | 1];} 8 void build(int l,int r,int rt) 9 { 10 if(l == r) {scanf("%d",&sum[rt]); return ;} 11 int m = (l + r) >> 1; 12 build(lson); 13 build(rson); 14 pushup(rt); 15 } 16 void update(int p,int add,int l,int r,int rt) 17 { 18 if(l == r) {sum[rt] += add;return ;} 19 int m = (l + r) >> 1; 20 if(p <= m) 21 update(p,add,l,m,rt << 1); 22 else 23 update(p,add,m+1,r,rt << 1 | 1); 24 pushup(rt); 25 } 26 LL query_sum(int ll,int rr,int l,int r,int rt) 27 { 28 if(ll <= l && rr >= r) return sum[rt]; 29 LL tot = 0; 30 int m = (l + r) >> 1; 31 if(ll <= m) 32 tot += query_sum(ll,rr,l,m,rt << 1); 33 if(rr > m) 34 tot += query_sum(ll,rr,m+1,r,rt << 1 | 1); 35 return tot; 36 } 37 int main() 38 { 39 int T,n,x,y,p = 1; 40 char s[12]; 41 scanf("%d",&T); 42 while(T--) 43 { 44 printf("Case %d:\n",p++); 45 scanf("%d",&n); 46 build(1,n,1); 47 while(~scanf("%s",s)) 48 { 49 if(!strcmp(s,"End")) break; 50 scanf("%d%d",&x,&y); 51 if(!strcmp(s,"Query")) {LL ans = query_sum(x,y,1,n,1);printf("%d\n",ans);} 52 if(!strcmp(s,"Add")) update(x,y,1,n,1); 53 if(!strcmp(s,"Sub")) update(x,-y,1,n,1); 54 } 55 } 56 return 0; 57 }
hdu 1754 I hate it(构造线段树,区间最大值查询,单点更新)
1 #include <cstdio> 2 #include <cstring> 3 #include <algorithm> 4 using namespace std; 5 typedef long long LL; 6 LL MAX[200000 << 2]; 7 #define lson l,m,rt << 1 8 #define rson m+1,r,rt << 1 | 1 9 void pushup(int rt){MAX[rt] = max(MAX[rt << 1] , MAX[rt << 1 | 1]);} 10 void build(int l,int r,int rt) 11 { 12 if(l == r) {scanf("%d",&MAX[rt]); return ;} 13 int m = (l + r) >> 1; 14 build(lson); 15 build(rson); 16 pushup(rt); 17 } 18 void update(int p,int add,int l,int r,int rt) 19 { 20 if(l == r) {MAX[rt] = add;return ;} 21 int m = (l + r) >> 1; 22 if(p <= m) 23 update(p,add,l,m,rt << 1); 24 else 25 update(p,add,m+1,r,rt << 1 | 1); 26 pushup(rt); 27 } 28 LL query_max(int ll,int rr,int l,int r,int rt) 29 { 30 if(ll <= l && rr >= r) return MAX[rt]; 31 LL ans = 0; 32 int m = (l + r) >> 1; 33 if(ll <= m) 34 ans = max(ans,query_max(ll,rr,l,m,rt << 1)); 35 if(rr > m) 36 ans = max(ans,query_max(ll,rr,m+1,r,rt << 1 | 1)); 37 return ans; 38 } 39 int main() 40 { 41 int n,m,x,y; 42 char ch; 43 while(~scanf("%d%d",&n,&m)) 44 { 45 build(1,n,1); 46 for(int i=0;i<m;i++) 47 { 48 getchar(); 49 scanf("%c%d%d",&ch,&x,&y); 50 if(ch == ‘Q‘) 51 { 52 int ans = query_max(x,y,1,n,1); 53 printf("%d\n",ans); 54 } 55 else 56 update(x,y,1,n,1); 57 } 58 } 59 return 0; 60 }
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原文地址:http://www.cnblogs.com/luosuo10/p/5699231.html