题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1869
转载请注明出处:http://blog.csdn.net/u012860063?viewmode=contents
8 7 0 1 1 2 2 3 3 4 4 5 5 6 6 7 8 8 0 1 1 2 2 3 3 4 4 5 5 6 6 7 7 0
Yes Yes
#include <cstdio>
#include <cstring>
#define INF 99999999
#define M 217
int n , m ,a ,b ,x;
int dis[M][M];
int min(int a,int b)
{
int m;
m = a < b ? a : b;
return m;
}
void Floyd()
{
for(int k = 0; k < n ; k++ )
{
for(int i = 0; i < n ; i++ )
{
for(int j = 0; j < n ; j++ )
{
dis[i][j]=min(dis[i][j],dis[i][k]+dis[k][j]);
}
}
}
}
void init()
{
for(int i = 0; i < n ; i++ )
{
for(int j = 0; j < n ; j++ )
{
if( i == j )
dis[i][j] = 0 ;//这一步必须归为零
else
dis[i][j]=INF;
}
}
}
int main()
{
int i, j;
int cont[M];
while(~scanf("%d%d",&n,&m))
{
init();
memset(cont,0,sizeof(cont));
for( i = 0; i < m; i++ )
{
scanf("%d%d",&a,&b);
dis[a][b] = dis[b][a] = 1;
}
Floyd();
int flag = 0;
for(i = 0; i < n; i++)
{
for(j = 0; j < n; j++)
{
if(dis[i][j] > 7)
{
flag = 1;
break;
}
}
}
if(flag)
printf("No\n");
else
printf("Yes\n");
}
return 0;
}
hdu1869 六度分离(Floyd),布布扣,bubuko.com
原文地址:http://blog.csdn.net/u012860063/article/details/38412617