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Time Limit: 7000/3500 MS (Java/Others)
Memory Limit: 131072/131072 K (Java/Others)
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> //#include <bits/stdc++.h> #include <stack> using namespace std; #define For(i,j,n) for(int i=j;i<=n;i++) #define mst(ss,b) memset(ss,b,sizeof(ss)); typedef long long LL; template<class T> void read(T&num) { char CH; bool F=false; for(CH=getchar();CH<‘0‘||CH>‘9‘;F= CH==‘-‘,CH=getchar()); for(num=0;CH>=‘0‘&&CH<=‘9‘;num=num*10+CH-‘0‘,CH=getchar()); F && (num=-num); } int stk[70], tp; template<class T> inline void print(T p) { if(!p) { puts("0"); return; } while(p) stk[++ tp] = p%10, p/=10; while(tp) putchar(stk[tp--] + ‘0‘); putchar(‘\n‘); } const LL mod=1e9+7; const double PI=acos(-1.0); const int inf=1e9; const int N=1e5+10; const int maxn=500+10; const double eps=1e-8; int prime[N],sum[N],a[N],cnt=0,n,d; void Init() { sum[1]=0; For(i,2,N-maxn) { if(!prime[i]) { for(int j=2*i;j<N-maxn;j+=i) { prime[j]=1; } sum[i]=sum[i-1]+1; } else sum[i]=sum[i-1]; } For(i,2,N-maxn) { if(!prime[i])a[++cnt]=i; } } inline int check(int x) { for(int i=1;i<=cnt;i++) { if(x%a[i]==0)return a[i]; if((LL)a[i]*a[i]>x||a[i]>n/d)break; } return x; } int main() { int t; read(t); Init(); while(t--) { read(n);read(d); n--; int le=min(check(d),n/d); printf("%d\n",sum[le]); } return 0; }
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原文地址:http://www.cnblogs.com/zhangchengc919/p/5699905.html