取序列对象中元素出现的次数

from collections import Iterable
def action(iterable):
    reslut = {}
    if not isinstance(iterable,Iterable):  #判断对象是否是可迭代    
        raise TypeError(‘is not iterable‘) #如果不是手动触发异常
    for item in iterable:                  #对对象进行迭代
        if item in reslut.keys():          #把元素和元素出现的次数
            reslut[item] += 1              #加到空的reslut字典中
        else:
            reslut[item] = 1
    return reslut

if __name__ == ‘__main__‘:
	data = [‘a‘,‘b‘,‘a‘,‘b‘,‘c‘,‘b‘,‘a‘,1,2,1,1,3,3,4,4,1,2,5,5]
	reslut = action(data)
	print reslut
结果:
{‘a‘: 3, 1: 4, ‘c‘: 1, ‘b‘: 3, 4: 2, 5: 2, 2: 2, 3: 2}

data = [‘a‘,‘b‘,‘a‘,‘b‘,‘c‘,‘b‘,‘a‘,1,2,1,1,3,3,4,4,1,2,5,5]
reslut = {}
for item in data:
　　reslut[item] = data.count(item)
else:
　　print reslut

结果也是一样的

data = [‘a‘,‘b‘,‘a‘,‘b‘,‘c‘,‘b‘,‘a‘,1,2,1,1,3,3,4,4,1,2,5,5]
reslut = { item:data.count(item) for item in data}
print reslut