368. Largest Divisible Subset

class Solution {
  public List<Integer> largestDivisibleSubset(int[] nums) {
    int n = nums.length;
    List<Integer> res = new ArrayList<>();
    if (n == 0)
      return res;

    //maxCount keeps maximum length of a subset that has nums[i] as the largest
    int[] maxCount = new int[n];
    //linkToPrev provides a link to previous number in the DivisibleSubset
    int[] linkToPrev = new int[n];
    Arrays.sort(nums);

    int maxInd = 0;
    for (int i = 0; i < n; ++i) {
      maxCount[i] = 1; //include itself in the subset
      linkToPrev[i] = -1; //-1 indicates a stop

      for (int divisor = i - 1; divisor >= 0; --divisor) {
        //iterate backward to see which divisors can be included
        if (nums[i] % nums[divisor] == 0) {
          int includeDivisor = maxCount[divisor] + 1;
          if (includeDivisor > maxCount[i]) {
            maxCount[i] = includeDivisor;
            linkToPrev[i] = divisor;
          }
        }
      }
      if (maxCount[i] > maxCount[maxInd]) {
        maxInd = i;
      }
    }

    while (maxInd != -1) {
      res.add(nums[maxInd]);
      maxInd = linkToPrev[maxInd];
    }
    return res;
  }
}