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两种操作, 一种将x, y这个格子+w, 另一种给出左下和右上坐标, 问你这个矩形中值的和。
#include <iostream> #include <vector> #include <cstdio> #include <cstring> #include <algorithm> #include <complex> #include <cmath> #include <map> #include <set> #include <string> #include <queue> #include <stack> #include <bitset> using namespace std; #define pb(x) push_back(x) #define ll long long #define mk(x, y) make_pair(x, y) #define lson l, m, rt<<1 #define mem(a) memset(a, 0, sizeof(a)) #define rson m+1, r, rt<<1|1 #define mem1(a) memset(a, -1, sizeof(a)) #define mem2(a) memset(a, 0x3f, sizeof(a)) #define rep(i, n, a) for(int i = a; i<n; i++) #define fi first #define se second typedef complex <double> cmx; typedef pair<int, int> pll; const double PI = acos(-1.0); const double eps = 1e-8; const int mod = 1e9+7; const int inf = 1061109567; const int dir[][2] = { {-1, 0}, {1, 0}, {0, -1}, {0, 1} }; const int maxn = 2e5+5; struct node { int x1, y1, x2, y2, w, id, sign; bool operator < (node a) const { return id < a.id; } }a[maxn], c[maxn*2]; int sum[500005], ans[maxn], n, m; int lowbit(int x) { return x & (-x); } void update(int x, int val) { while(x <= m) { sum[x] += val; x += lowbit(x); } } int query(int x) { int ret = 0; while(x) { ret += sum[x]; x -= lowbit(x); } return ret; } bool cmp(const node& a, const node& b) { if(a.x1 != b.x1) return a.x1 < b.x1; return a.sign < b.sign; } void cdq(int l, int r) { if(l == r) return ; int m = l+r>>1; cdq(l, m); cdq(m+1, r); int num = 0; for(int i = l; i <= m; i++) { if(a[i].sign == 1) { c[num++] = a[i]; } } for(int i = m + 1; i <= r; i++) { if(a[i].sign == 2) { c[num++] = a[i]; c[num-1].x1--; c[num++] = a[i]; c[num-1].x1 = c[num-1].x2; c[num-1].sign = 3; } } sort(c, c+num, cmp); for(int i = 0; i < num; i++) { if(c[i].sign == 1) { update(c[i].y1, c[i].w); } else if(c[i].sign == 2) { ans[c[i].id] -= (query(c[i].y2) - query(c[i].y1 - 1)); } else { ans[c[i].id] += (query(c[i].y2) - query(c[i].y1 - 1)); } } for(int i = l; i <= m; i++) { if(a[i].sign == 1) { update(a[i].y1, -a[i].w); } } } int main() { freopen ( "locust.in" , "r" , stdin ) ; freopen ( "locust.out" , "w" , stdout ) ; while(cin>>m>>n) { for(int i = 1; i <= n; i++) { scanf("%d", &a[i].sign); if(a[i].sign == 1) { scanf("%d%d%d", &a[i].x1, &a[i].y1, &a[i].w); } else { scanf("%d%d%d%d", &a[i].x1, &a[i].y1, &a[i].x2, &a[i].y2); } a[i].id = i; } mem(sum); mem(ans); cdq(1, n); for(int i = 1; i <= n; i++) { if(a[i].sign == 2) { printf("%d\n", ans[i]); } } } return 0; }
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原文地址:http://www.cnblogs.com/yohaha/p/5703150.html