递增数列中和为s的两个数字，和为s的连续正数序列

 1   和为s的两个数，利用begin，end两个位置标志和为s前后两个元素，当和大于s，end前移，和小于s，begin后移
     vector<int> FindNumbersWithSum(vector<int> array,int sum) {
 2         vector<int>res;
 3         if(array.size()==0)
 4             return res;
 5         bool found=false;
 6         int cursum=0;
 7         int begin=0;
 8         int end=array.size()-1;
 9         while(begin<end)
10             {
11             cursum=array[begin]+array[end];
12             if(cursum==sum)
13                 {
14                 res.push_back(array[begin]);
15                 res.push_back(array[end]);
16                 found=true;
17                 break;
18             }
19             else if(cursum<sum)
20                 begin++;
21             else
22                 end--;
23                 
24                 
25         }
26         return res;
27     }

 1     void addtoresult(int small,int big,vector<int>&num,vector<vector<int>>&res)
 2     {
 3         num.clear();//每次记录新的序列前应该清除旧的序列
 4         for(int i=small;i<=big;i++)
 5             {
 6             num.push_back(i);
 7         }
 8         res.push_back(num);
 9     }
10     vector<vector<int> > FindContinuousSequence(int sum) {
11         vector<vector<int>>res;
12         vector<int>num;
13         if(sum==1 ||sum==2)
14         {
15             return res;
16         }
17         int small=1;
18         int big=2;
19         int middle=(1+sum)/2;
20         int cursum=small+big;
21         while(small<middle)
22         {
23             if(cursum==sum)
24             {
25                 addtoresult(small,big,num,res);
26             }
27             while(cursum>sum&&small<middle)
28                 {
29                 cursum-=small;
30                 small++;
31                 if(cursum==sum)
32                     addtoresult(small,big,num,res);
33             }
34             big++;
35             cursum+=big;
36         }
37         return res;
38     }