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Flip Game I && II

时间:2016-07-30 01:42:29      阅读:276      评论:0      收藏:0      [点我收藏+]

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You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip two consecutive "++" into "--". The game ends when a person can no longer make a move and therefore the other person will be the winner.

Write a function to determine if the starting player can guarantee a win.

For example, given s = "++++", return true. The starting player can guarantee a win by flipping the middle "++" to become "+--+".

Code is from: https://discuss.leetcode.com/topic/27287/short-java-ruby?show=64350

1     public boolean canWin(String s) {
2         for (int i=-1; (i = s.indexOf("++", i+1)) >= 0; )
3             if (!canWin(s.substring(0, i) + "-" + s.substring(i + 2))) return true;
4         return false;
5     }

 

Flip Game I && II

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原文地址:http://www.cnblogs.com/beiyeqingteng/p/5720056.html

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