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Sum square difference

时间:2014-05-07 20:23:43      阅读:338      评论:0      收藏:0      [点我收藏+]

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简单:

e sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 bubuko.com,布布扣 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

bubuko.com,布布扣
def naturalnumber(n):
    sumnatural = 0
    for i in xrange(1,n+1):
        sumnatural += i * i
    return sumnatural

def squarenumber(n):
    sumsquare = 0
    for i in xrange(1,n+1):
        sumsquare += i
    return sumsquare * sumsquare

print squarenumber(100) - naturalnumber(100)
bubuko.com,布布扣

C:\webpy\webpy\Scripts\python.exe C:/pycode/euler.py
25164150

Process finished with exit code 0

Sum square difference,布布扣,bubuko.com

Sum square difference

标签:style   blog   class   code   java   ext   

原文地址:http://www.cnblogs.com/aguncn/p/3713742.html

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