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题意:给 n 个数,每次可以把4个连续的数字翻转,问你能不能形成1-n的环状排列。
析:找一下奇偶性,写几个数试试,就会找到规律。
代码如下:
#include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring> #include <set> #include <queue> #include <algorithm> #include <vector> #include <map> #include <cctype> using namespace std ; typedef long long LL; typedef pair<int, int> P; const int INF = 0x3f3f3f3f; const double inf = 0x3f3f3f3f3f3f3f; const double eps = 1e-12; const int maxn = 1e6 + 5; const int dr[] = {0, 0, -1, 1}; const int dc[] = {-1, 1, 0, 0}; int n; int a[505]; int main(){ int T; cin >> T; while(T--){ scanf("%d", &n); int cnt = 0; for(int i = 0; i < n; ++i){ scanf("%d", &a[i]); for(int j = 0; j < i; ++j) cnt += (a[i] < a[j]); } if(cnt & 1 && n & 1) cout << "impossible\n"; else cout << "possible\n"; } return 0; }
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原文地址:http://www.cnblogs.com/dwtfukgv/p/5727331.html