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HDU 5791 Two

时间:2016-08-02 20:37:02      阅读:248      评论:0      收藏:0      [点我收藏+]

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Two

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 163    Accepted Submission(s): 72


Problem Description
Alice gets two sequences A and B. A easy problem comes. How many pair of sequence A‘ and sequence B‘ are same. For example, {1,2} and {1,2} are same. {1,2,4} and {1,4,2} are not same. A‘ is a subsequence of A. B‘ is a subsequence of B. The subsequnce can be not continuous. For example, {1,1,2} has 7 subsequences {1},{1},{2},{1,1},{1,2},{1,2},{1,1,2}. The answer can be very large. Output the answer mod 1000000007.
 

 

Input
The input contains multiple test cases.

For each test case, the first line cantains two integers N,M(1≤N,M≤1000). The next line contains N integers. The next line followed M integers. All integers are between 1 and 1000.
 

 

Output
For each test case, output the answer mod 1000000007.
 

 

Sample Input
3 2
1 2 3
2 1
3 2
1 2 3
1 2
 
Sample Output
2
3
 
Author
ZSTU
 
/* ***********************************************
Author        :guanjun
Created Time  :2016/8/2 14:20:58
File Name     :p511.cpp
************************************************ */
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <stdio.h>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <math.h>
#include <stdlib.h>
#include <iomanip>
#include <list>
#include <deque>
#include <stack>
#define ull unsigned long long
#define ll long long
#define mod 1000000007
#define INF 0x3f3f3f3f
#define maxn 10010
#define cle(a) memset(a,0,sizeof(a))
const ull inf = 1LL << 61;
const double eps=1e-5;
using namespace std;
priority_queue<int,vector<int>,greater<int> >pq;
struct Node{
    int x,y;
};
struct cmp{
    bool operator()(Node a,Node b){
        if(a.x==b.x) return a.y> b.y;
        return a.x>b.x;
    }
};

bool cmp(int a,int b){
    return a>b;
}
ll dp[1100][1100];
int n,m;
int a[1100];
int b[1100];
int main()
{
    #ifndef ONLINE_JUDGE
    freopen("in.txt","r",stdin);
    #endif
    //freopen("out.txt","w",stdout);
    while(cin>>n>>m){
        for(int i=1;i<=n;i++)scanf("%d",&a[i]);
        for(int j=1;j<=m;j++)scanf("%d",&b[j]);
        cle(dp);
        ll x;
        for(int i=1;i<=n;i++){
            for(int j=1;j<=m;j++){
                if(a[i]==b[j])x=dp[i-1][j-1]+1;
                else x=0;
                dp[i][j]=(dp[i][j]+dp[i-1][j]+dp[i][j-1]-dp[i-1][j-1]+mod)%mod;
                dp[i][j]=(dp[i][j]+x)%mod;
            }
        }
        printf("%I64d\n",dp[n][m]);
    }
    return 0;
}

 

HDU 5791 Two

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原文地址:http://www.cnblogs.com/pk28/p/5730375.html

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