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Time Limit: 5000/2500 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 119 Accepted Submission(s): 73
贪心。尽量一个个选。考虑到前缀不能为负,可以倒着扫一遍
/* *********************************************** Author :guanjun Created Time :2016/8/2 12:04:29 File Name :p512.cpp ************************************************ */ #include <iostream> #include <cstring> #include <cstdlib> #include <stdio.h> #include <algorithm> #include <vector> #include <queue> #include <set> #include <map> #include <string> #include <math.h> #include <stdlib.h> #include <iomanip> #include <list> #include <deque> #include <stack> #define ull unsigned long long #define ll long long #define mod 90001 #define INF 0x3f3f3f3f #define maxn 1000010 #define cle(a) memset(a,0,sizeof(a)) const ull inf = 1LL << 61; const double eps=1e-5; using namespace std; priority_queue<int,vector<int>,greater<int> >pq; struct Node{ int x,y; }; struct cmp{ bool operator()(Node a,Node b){ if(a.x==b.x) return a.y> b.y; return a.x>b.x; } }; bool cmp(int a,int b){ return a>b; } int a[maxn]; int vis[maxn]; int main() { #ifndef ONLINE_JUDGE // freopen("in.txt","r",stdin); #endif //freopen("out.txt","w",stdout); int n; while(cin>>n){ int mark=0; cle(vis); for(int i=1;i<=n;i++){ scanf("%d",&a[i]); if(a[i]<0)mark=1,vis[i]=1; } if(!mark){ printf("%d\n",n);continue; } ll ans=0; for(int i=n;i>=1;i--){ if(vis[i]){ ll sum=a[i]; while(sum<0){ i--; sum+=a[i]; } } ans++; } printf("%I64d\n",ans); } return 0; }
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原文地址:http://www.cnblogs.com/pk28/p/5730319.html