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Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
class Solution { public: int minPathSum(vector<vector<int>>& grid) { int M=grid.size(); int N=grid[0].size(); if(M==0) return 0; vector<vector<int>> res(grid); for(int j=1;j<N;j++) //先要把边界的算出来 res[0][j]+=res[0][j-1]; for(int i=1;i<M;i++) res[i][0]+=res[i-1][0]; for(int i=1;i<M;i++) for(int j=1;j<N;j++) { res[i][j]=min(res[i-1][j],res[i][j-1])+res[i][j]; } return res[M-1][N-1]; } };
leetcode No64. Minimum Path Sum
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原文地址:http://blog.csdn.net/u011391629/article/details/52097867