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Description
Input
Output
Sample Input
1 3 8 9 10 10 10 10 -10 10 10 10 -11 -1 0 2 11 10 -20 -11 -11 10 11 2 10 -10 -10
Sample Output
52
#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#include <queue>
#include <vector>
#include <iomanip>
#include <math.h>
#include <map>
using namespace std;
#define FIN freopen("input.txt","r",stdin);
#define FOUT freopen("output.txt","w",stdout);
#define INF 0x3f3f3f3f
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
typedef long long LL;
int dp[1005][1005];
int M[25][1005];
int main()
{
//FIN
int T;
scanf("%d",&T);
while(T--)
{
int n,m;
scanf("%d%d",&n,&m);
for(int i=1; i<=n; i++)
for(int j=1; j<=m; j++)
{
scanf("%d",&M[i][j]);
}
for(int i=0;i<=n;i++) dp[i][0]=-INF;
for(int i=0;i<=m;i++) dp[0][i]=-INF;
dp[0][1]=dp[1][0]=0;
for(int i=1; i<=n; i++)
for(int j=1; j<=m; j++){
dp[i][j]=max(dp[i-1][j],dp[i][j-1]);
for(int k=2;k<=m;k++){
if(j/k==(double)j/k) dp[i][j]=max(dp[i][j],dp[i][j/k]);
}
dp[i][j]+=M[i][j];
}
printf("%d\n",dp[n][m]);
}
}
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原文地址:http://www.cnblogs.com/Hyouka/p/5732852.html