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LeetCode226:Invert Binary Tree 二叉树反转

时间:2016-08-04 19:52:02      阅读:204      评论:0      收藏:0      [点我收藏+]

标签:二叉树

题目

226. Invert Binary Tree

QuestionEditorial Solution

 My Submissions

  • Total Accepted: 109341

  • Total Submissions: 230799

  • Difficulty: Easy

Invert a binary tree.

     4
   /     2     7
 / \   / 1   3 6   9

to

     4
   /     7     2
 / \   / 9   6 3   1

Trivia:
This problem was inspired by this original tweet by Max Howell:

Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off.
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* invertTree(TreeNode* root) {
        TreeNode *p,*q;
        p = NULL;
        q = NULL;
        if(root != NULL)
        {
            p = root->left;
            q = root->right;
            root->left = q;
            root->right = p;
            invertTree(root->left);
            invertTree(root->right);
        }
        return root;
    }
};


LeetCode226:Invert Binary Tree 二叉树反转

标签:二叉树

原文地址:http://qiaopeng688.blog.51cto.com/3572484/1834271

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