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题目链接:
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 181 Accepted Submission(s): 119
/************************************************ ┆ ┏┓ ┏┓ ┆ ┆┏┛┻━━━┛┻┓ ┆ ┆┃ ┃ ┆ ┆┃ ━ ┃ ┆ ┆┃ ┳┛ ┗┳ ┃ ┆ ┆┃ ┃ ┆ ┆┃ ┻ ┃ ┆ ┆┗━┓ ┏━┛ ┆ ┆ ┃ ┃ ┆ ┆ ┃ ┗━━━┓ ┆ ┆ ┃ AC代马 ┣┓┆ ┆ ┃ ┏┛┆ ┆ ┗┓┓┏━┳┓┏┛ ┆ ┆ ┃┫┫ ┃┫┫ ┆ ┆ ┗┻┛ ┗┻┛ ┆ ************************************************ */ #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <bits/stdc++.h> #include <stack> using namespace std; #define For(i,j,n) for(int i=j;i<=n;i++) #define mst(ss,b) memset(ss,b,sizeof(ss)); typedef long long LL; template<class T> void read(T&num) { char CH; bool F=false; for(CH=getchar();CH<‘0‘||CH>‘9‘;F= CH==‘-‘,CH=getchar()); for(num=0;CH>=‘0‘&&CH<=‘9‘;num=num*10+CH-‘0‘,CH=getchar()); F && (num=-num); } int stk[70], tp; template<class T> inline void print(T p) { if(!p) { puts("0"); return; } while(p) stk[++ tp] = p%10, p/=10; while(tp) putchar(stk[tp--] + ‘0‘); putchar(‘\n‘); } const LL mod=1e9+7; const double PI=acos(-1.0); const int inf=1e9; const int N=1e6+10; const int maxn=2e3+14; const double eps=1e-12; /* int f[110],sg[110]; inline void Init() { For(i,0,100) { mst(f,0); For(j,1,i) { f[sg[i-j]]=1; } if(i>=3) { For(j,1,i-1) For(k,1,i-1) { if(j+k<i)f[sg[j]^sg[k]^sg[i-j-k]]=1; } } For(j,0,100)if(!f[j]){sg[i]=j;break;} cout<<i<<" "<<sg[i]<<endl; } } */ int main() { //Init(); int t; read(t); while(t--) { int n,sum=0,x; read(n); For(i,1,n) { read(x); if(x%8==7)sum^=x+1; else if(x%8==0&&x)sum^=x-1; else sum^=x; } if(sum==0)cout<<"Second player wins.\n"; else cout<<"First player wins.\n"; } return 0; }
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原文地址:http://www.cnblogs.com/zhangchengc919/p/5738694.html