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思路:水题,直接搜
1 #include "map" 2 #include "queue" 3 #include "math.h" 4 #include "stdio.h" 5 #include "string.h" 6 #include "iostream" 7 #include "algorithm" 8 #define abs(x) x > 0 ? x : -x 9 #define max(a,b) a > b ? a : b 10 #define min(a,b) a < b ? a : b 11 12 using namespace std; 13 14 int z2,x2,y2,n; 15 int d[6][3]= {{0,0,1},{0,1,0},{0,0,-1},{0,-1,0},{1,0,0},{-1,0,0}}; 16 bool Map[15][15][15],vis[15][15][15]; 17 18 struct Node{ 19 int zz,xx,yy; 20 int step; 21 }; 22 23 void Bfs(int z,int x,int y) 24 { 25 memset(vis,0,sizeof(vis)); 26 queue<Node>Q; 27 Node now,next; 28 29 now.zz = z; 30 now.xx = x; 31 now.yy = y; 32 now.step = 0; 33 vis[z][x][y] = 1; 34 35 Q.push(now); 36 37 while(!Q.empty()) 38 { 39 now = Q.front(); 40 Q.pop(); 41 42 if(now.zz==z2 && now.xx==x2 && now.yy==y2) 43 { 44 printf("%d %d\n",n,now.step); 45 return; 46 } 47 48 for(int i=0; i<6; i++) 49 { 50 next.zz = now.zz + d[i][0]; 51 next.xx = now.xx + d[i][1]; 52 next.yy = now.yy + d[i][2]; 53 next.step = now.step + 1; 54 55 if(Map[next.zz][next.xx][next.yy] && !vis[next.zz][next.xx][next.yy]) 56 { 57 vis[next.zz][next.xx][next.yy] = 1; 58 Q.push(next); 59 } 60 } 61 } 62 printf("NO ROUTE\n"); 63 } 64 65 int main() 66 { 67 int x1,y1,z1,i,j,k; 68 char s[20],c; 69 while(~scanf("%s%d",s,&n)) 70 { 71 memset(Map,0,sizeof(Map)); 72 for(i=1; i<=n; i++) 73 for(j=1; j<=n; j++) 74 { 75 getchar(); 76 for(k=1; k<=n; k++) 77 { 78 scanf("%c",&c); 79 if(c==‘O‘) 80 Map[i][j][k] = 1; 81 if(c==‘X‘) 82 Map[i][j][k] = 0; 83 } 84 } 85 86 scanf("%d%d%d%d%d%d",&x1,&y1,&z1,&x2,&y2,&z2); 87 z1+=1,x1+=1,y1+=1,z2+=1,x2+=1,y2+=1; 88 getchar(); 89 gets(s); 90 91 Bfs(z1,x1,y1); 92 } 93 return 0; 94 }
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原文地址:http://www.cnblogs.com/max88888888/p/5741280.html