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基础-DP

时间:2016-08-07 21:34:10      阅读:136      评论:0      收藏:0      [点我收藏+]

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Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave … 
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ? 
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Input

The first line contain a integer T , the number of cases. 
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

Output

One integer per line representing the maximum of the total value (this number will be less than 2 31).

Sample Input

1
5 10
1 2 3 4 5
5 4 3 2 1

Sample Output

14
#include<iostream>  
using namespace std;   
#include<math.h>
#include<string.h>  
#define maxn 100000  
long long d[maxn+5];  
int max(int a,int b)  
{  
    if(a>b)
        return a;  
    else 
        return b;  
}  
int main()  
{  
    int t,n,m,i,j;
    int V[1005],N[1005];  
    cin>>t;  
    while(t--)  
    {
        memset(d,0,sizeof(d));  
        cin>>n>>m;  
        for(i=0;i<n;i++)  
            cin>>V[i];  
        for(j=0;j<n;j++)  
            cin>>N[j];  
        for(i=0;i<n;i++)  
            for(j=m;j>=N[i];j--)  
        {  
            d[j]=max(d[j],d[j-N[i]]+V[i]);
        }  
        cout<<d[m]<<endl;  
    }  
    return 0;  
}  

 

基础-DP

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原文地址:http://www.cnblogs.com/lsb666/p/5746961.html

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