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Time Limit: 5000/2500 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
2013 ACM/ICPC Asia Regional Chengdu Online
#include<bits/stdc++.h> using namespace std; #define ll __int64 #define esp 0.00000000001 const int N=1e5+10,M=1e6+10,inf=1e9+10,mod=1000000007; int a[N]; int flag[40]; void init() { memset(flag,0,sizeof(flag)); } void update(int x,int hh) { int sum=0; while(x) { flag[sum++]+=x%2*hh; x>>=1; } } int getnum() { int ans=0; for(int i=0;i<=35;i++) { if(flag[i]) ans+=1<<i; } return ans; } int main() { int x,y,z,i,t; int T,cas=1; scanf("%d",&T); while(T--) { init(); scanf("%d%d",&x,&y); for(i=1;i<=x;i++) scanf("%d",&a[i]); int st=1; int en=1; int cnt=1; ll ans=0; int qu=0; while(1) { while(getnum()<y&&en<=x) update(a[en++],1); if(getnum()<y) { ans+=(ll)(en-st)*(en-st+1)/2; break; } ans+=max(0,en-st-1); update(a[st++],-1); } printf("Case #%d: %I64d\n",cas++,ans); } return 0; }
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原文地址:http://www.cnblogs.com/jhz033/p/5747475.html