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题目链接:
Time Limit: 8000/4000 MS (Java/Others)
Memory Limit: 65536/65536 K (Java/Others)
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <bits/stdc++.h> #include <stack> #include <map> using namespace std; #define For(i,j,n) for(int i=j;i<=n;i++) #define mst(ss,b) memset(ss,b,sizeof(ss)); typedef long long LL; template<class T> void read(T&num) { char CH; bool F=false; for(CH=getchar();CH<‘0‘||CH>‘9‘;F= CH==‘-‘,CH=getchar()); for(num=0;CH>=‘0‘&&CH<=‘9‘;num=num*10+CH-‘0‘,CH=getchar()); F && (num=-num); } int stk[70], tp; template<class T> inline void print(T p) { if(!p) { puts("0"); return; } while(p) stk[++ tp] = p%10, p/=10; while(tp) putchar(stk[tp--] + ‘0‘); putchar(‘\n‘); } const LL mod=1e9+7; const double PI=acos(-1.0); const int inf=1e18; const int N=1e5+10; const int maxn=5e3+4; const double eps=1e-12; stack<int>a,b,c,d; char s[10],st[10],str[10]; LL temp[N]; int main() { int Case=0; LL x; while(1) { int n,cnt=0; read(n); if(n==0)break; while(!a.empty())a.pop(); while(!b.empty())b.pop(); while(!c.empty())c.pop(); printf("Case #%d:\n",++Case); For(i,1,n) { scanf("%s%s",s,str); if(s[0]==‘p‘) { if(s[1]==‘u‘) { scanf("%lld",&x); temp[++cnt]=x; if(str[0]==‘A‘)a.push(cnt); else b.push(cnt); } else { if(str[0]==‘A‘&&!a.empty()) { printf("%lld\n",temp[a.top()]); a.pop(); } else if(str[0]==‘B‘&&!b.empty()) { printf("%lld\n",temp[b.top()]); b.pop(); } else { printf("%lld\n",temp[c.top()]); c.pop(); } } } else { scanf("%s",st); while(!a.empty()||!b.empty()) { int A,B; if(a.empty())A=0; else A=a.top(); if(b.empty())B=0; else B=b.top(); if(A>B) { a.pop(); d.push(A); } else { b.pop(); d.push(B); } } while(!d.empty()) { c.push(d.top()); d.pop(); } } } } return 0; }
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原文地址:http://www.cnblogs.com/zhangchengc919/p/5755076.html