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Time Limit: 15000MS | Memory Limit: 228000K | |
Total Submissions: 20015 | Accepted: 5974 | |
Case Time Limit: 5000MS |
Description
Input
Output
Sample Input
6 -45 22 42 -16 -41 -27 56 30 -36 53 -37 77 -36 30 -75 -46 26 -38 -10 62 -32 -54 -6 45
Sample Output
5
Hint
Source
#include <cstdio> #include <algorithm> #include <vector> #define ll long long using namespace std; const int MAXN = 4000+5; int a[MAXN], b[MAXN], c[MAXN], d[MAXN]; int cd[MAXN*MAXN]; int n; pair<vector<int>::iterator, vector<int>::iterator> it; void solve() { for(int i = 0; i < n; ++i){ for(int j = 0; j < n; ++j){ cd[i*n+j] = c[i]+d[j]; } } sort(cd, cd+n*n); ll res = 0; for(int i = 0; i < n; ++i){ for(int j = 0; j < n; ++j){ int c_d = -(a[i]+b[j]); it = equal_range(cd, cd+n*n, c_d); res += it.second-it.first; } } printf("%I64d\n", res); } int main() { scanf("%d", &n); for(int i = 0; i < n; ++i) scanf("%d%d%d%d", &a[i], &b[i], &c[i], &d[i]); solve(); return 0; }
POJ 2785 4 Values whose Sum is 0
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原文地址:http://www.cnblogs.com/inmoonlight/p/5758303.html