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Time Limit: 4000/2000 MS (Java/Others)
Memory Limit: 65536/65536 K (Java/Others)
#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <bits/stdc++.h> #include <stack> #include <map> using namespace std; #define For(i,j,n) for(int i=j;i<=n;i++) #define mst(ss,b) memset(ss,b,sizeof(ss)); typedef long long LL; template<class T> void read(T&num) { char CH; bool F=false; for(CH=getchar();CH<‘0‘||CH>‘9‘;F= CH==‘-‘,CH=getchar()); for(num=0;CH>=‘0‘&&CH<=‘9‘;num=num*10+CH-‘0‘,CH=getchar()); F && (num=-num); } int stk[70], tp; template<class T> inline void print(T p) { if(!p) { puts("0"); return; } while(p) stk[++ tp] = p%10, p/=10; while(tp) putchar(stk[tp--] + ‘0‘); putchar(‘\n‘); } const LL mod=1e9+7; const double PI=acos(-1.0); const int inf=1e18; const int N=1e5+10; const int maxn=5e3+4; const double eps=1e-12; struct node { int a,id; }po[N]; int cmp(node x,node y) { if(x.a==y.a)return x.id<y.id; return x.a<y.a; } int main() { int t,Case=0,n; read(t); while(t--) { printf("Case #%d: ",++Case); read(n); int sum=0; For(i,1,n) { read(po[i].a); sum+=po[i].a; po[i].id=i; } int flag=0; sort(po+1,po+n+1,cmp); For(i,1,n) { if(po[i].a>=i) { flag=1; break; } } if(flag)printf("No\n"); else { printf("Yes\n"); printf("%d\n",sum); int num=0; For(i,1,n) { for(int j=1;j<=po[i].a;j++) { printf("%d %d\n",po[i].id,po[j].id); } } } } return 0; }
hdu-5813 Elegant Construction(贪心)
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原文地址:http://www.cnblogs.com/zhangchengc919/p/5759375.html