row_number() 函数

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工作中遇到一个需求 无采购多次付款申请列表。用到的sql如下

select b.ID,
       A.TITLE,
       A.BILL_NUMBER,
       A.COST_FIRST_TYPE_NAME,
       A.CREATOR_NAME,
       A.APPDATE,
       A.PAYMENT_COMPANY_NAME,
       A.SUPPLIER_NAME,
       A.CONTRACT_AMOUNT,
       A.HAVE_USE_TOTAL_AMOUNT,
       A.HAVE_PAID_TOTAL_AMOUNT,
       A.PAYMENT_ORDER_AMOUNT,
       A.PAYMENT_COUNT,
       ‘发起付款‘ as NewViewField1,
       B.STARTTIME,
       a.id as payid
  from CE_CORPORATE_PAYMENT A,
       TW_HORIZON_Instance B,
       TWR_HORIZON_Instance C,
       (select *
          from (select a.*,
                       row_number() over(partition by a.workid order by a.version desc) rownumber
                  from tw_horizon_author a)
         where rownumber = 1) D,
       (select distinct e.dataid, e.userid, e.status
          from TD_HORIZON_User E
         where e.userid = ‘HZ1794a1472031d901473402ca5b6600‘
           and e.status = ‘3‘) E
 where a.id = c.dataid
   and b.id = c.workid
   and c.workid = d.workid
   and c.workid = e.dataid
   and d.flowstatus = 7
   and e.userid = ‘HZ1794a1472031d901473402ca5b6600‘
   and a.bill_number = ‘20151103dgfk0103‘ 
  and a.PAYMENT_ORDER_AMOUNT > a.PAYMENT_ORDER
   and a.PAYMENT_ORDER = 1  
   and to_number(a.PAYMENT_COUNT) < to_number(a.PAYMENT_ORDER_AMOUNT)
   and to_number(a.HAVE_USE_TOTAL_AMOUNT) < to_number(a.CONTRACT_AMOUNT)
   and a.IS_HAVE_CONTRACT = ‘有合同‘
   and a.url_type_code = ‘0‘
 order by B.STARTTIME desc

这个就是根据流程实例workid分组之后，然后按照流程实例版本号进行倒序排列，而此函数的值就是内部排序后的顺序编号，

where后边取rownumber=‘1‘指的就是最新的版本号了。

注：tw_horizon_author 为流程轨迹表

row_number() 函数

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原文地址：http://www.cnblogs.com/zhouyanan/p/5761757.html