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题意:....
析:从下往上算即可,水DP。
代码如下:
#pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring> #include <set> #include <queue> #include <algorithm> #include <vector> #include <map> #include <cctype> #include <stack> using namespace std; typedef long long LL; typedef pair<int, int> P; const int INF = 0x3f3f3f3f; const double inf = 0x3f3f3f3f3f3f; const LL LNF = 100000000000000000; const double PI = acos(-1.0); const double eps = 1e-8; const int maxn = 1e2 + 5; const int mod = 1e9 + 7; const char *mark = "+-*"; const int dr[] = {-1, 0, 1, 0}; const int dc[] = {0, 1, 0, -1}; int n, m; inline bool is_in(int r, int c){ return r >= 0 && r < n && c >= 0 && c < m; } inline LL Max(LL a, LL b){ return a < b ? b : a; } inline LL Min(LL a, LL b){ return a > b ? b : a; } inline int Max(int a, int b){ return a < b ? b : a; } inline int Min(int a, int b){ return a > b ? b : a; } int a[maxn][maxn]; int d[maxn][maxn]; int main(){ int T; cin >> T; while(T--){ memset(d, 0, sizeof(d)); scanf("%d", &n); for(int i = 0; i < n; ++i) for(int j = 0; j <= i; ++j) scanf("%d", &a[i][j]); for(int i = 0; i < n; ++i) d[n-1][i] = a[n-1][i]; for(int i = n-2; i >= 0; --i) for(int j = 0; j <= i; ++j) d[i][j] = Max(d[i+1][j], d[i+1][j+1]) + a[i][j]; printf("%d\n", d[0][0]); } return 0; }
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原文地址:http://www.cnblogs.com/dwtfukgv/p/5767770.html