UVa10082

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10082 WERTYU
A common typing error is to place the hands on
the keyboard one row to the right of the correct
position. So ‘Q’ is typed as ‘W’ and ‘J’ is typed
as ‘K’ and so on. You are to decode a message
typed in this manner.
Input
Input consists of several lines of text. Each line may contain digits, spaces, upper case letters (except
Q, A, Z), or punctuation shown above [except back-quote (`)]. Keys labelled with words [Tab, BackSp,
Control, etc.] are not represented in the input.
Output
You are to replace each letter or punction symbol by the one immediately to its left on the ‘QWERTY’
keyboard shown above. Spaces in the input should be echoed in the output.
Sample Input
O S, GOMR YPFSU/
Sample Output
I AM FINE TODAY.

题意：

你在用键盘进行输入的时候会按错，输出的字母是你想要输入字母的右边一个字母或者字符。注意，显示的一定都是可见的字符。

输入：

一行字符串，表示显示在屏幕上的一串字符。

输出：

一行字符串，表示你想要输入的字符串。

分析：

注意到如果输入是空格的话，输出仍然是空格。由于输出都是输入的字符在键盘位置的右边一个，所以将键盘字符一次存入keybo数组里面，依次地读入字符串中每个字符，在keybo中找到该字符的位置，并输出位于keybo上一位的字符即可。

 1 #include <cstdio>
 2 #include <iostream>
 3 #include <cstring>
 4 #include <cmath>
 5 using namespace std;
 6 char keybo[] = "`1234567890-=QWERTYUIOP[]\\ASDFGHJKL;‘ZXCVBNM,./";
 7 void print_correct(char str[]){
 8     int len = strlen(str);
 9     int llen = strlen(keybo);
10     for(int i = 0 ; i < len ; i++){
11         if(str[i] == ‘ ‘){
12             printf(" ");
13             continue;
14         }
15         for(int j = 0 ; j < llen ; j++)
16             if(str[i] == keybo[j]){
17                 printf("%c",keybo[j - 1]);
18                 break;
19             }
20     }
21 }
22 int main(){
23     char str[100];
24     while(gets(str)){
25         print_correct(str);
26         printf("\n");
27     }
28     return 0;
29 }

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UVa10082

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原文地址：http://www.cnblogs.com/cyb123456/p/5769123.html