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Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
For example,
Consider the following matrix:
[ [1, 3, 5, 7], [10, 11, 16, 20], [23, 30, 34, 50] ]
Given target =3, returntrue.
class Solution { public: bool searchMatrix(vector<vector<int> > &matrix, int target) { int m = matrix.size(); int n = matrix[0].size(); int c = n-1; for(int r = 0;(r<m)&&(c>=0);) { if(matrix[r][c]>target) { c--; } else if(matrix[r][c]<target) { r++; } else return true; } return false; } //每次比较行末,由于已经排序好,可以进行行列删除 };
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原文地址:http://www.cnblogs.com/LaplaceAkuir/p/5772553.html