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Given a set of candidate numbers (C) and a target number (T), find all unique combinations in C where the candidate numbers sums to T.
The same repeated number may be chosen from C unlimited number of times.
Note:
For example, given candidate set 2,3,6,7
and target 7
,
A solution set is: [7]
[2, 2, 3]
题意:
给定一个候选集合,集合中的元素以非递减方式存放。给定一个目标值T。
输出所有唯一的组合。
思路:
由于不能出现重复元组,所以我们先将candidate set进行排序,然后规定比新插入的元素不能比当前元素小。
采用DFS思想即可。
解法如下:
class Solution { private: vector<int> ans; vector<vector<int> > ret; public: void DFS(int start,vector<int> &candidates, int target){ if(target==0){ ret.push_back(ans); return; } for(int i=start;i<candidates.size();++i){ if(target <candidates[i]) return; ans.push_back(candidates[i]); DFS(i,candidates,target-candidates[i]); ans.pop_back(); } } vector<vector<int> > combinationSum(vector<int> &candidates, int target) { ans.clear(); ret.clear(); if(!target || !candidates.size()) return ret; sort(candidates.begin(),candidates.end()); DFS(0,candidates,target); return ret; } };
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作者:Double_Win 出处: http://www.cnblogs.com/double-win/p/3896010.html 声明: 由于本人水平有限,文章在表述和代码方面如有不妥之处,欢迎批评指正~ |
[LeetCode: 题解] Combination Sum,布布扣,bubuko.com
[LeetCode: 题解] Combination Sum
标签:des style blog http color os io strong
原文地址:http://www.cnblogs.com/double-win/p/3899927.html