*Maximum Product of Word Lengths

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Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no such two words exist, return 0.

Example 1:

Given ["abcw", "baz", "foo", "bar", "xtfn", "abcdef"]
Return 16
The two words can be "abcw", "xtfn".

Example 2:

Given ["a", "ab", "abc", "d", "cd", "bcd", "abcd"]
Return 4
The two words can be "ab", "cd".

Example 3:

Given ["a", "aa", "aaa", "aaaa"]
Return 0
No such pair of words.

Credits:
Special thanks to @dietpepsi for adding this problem and creating all test cases.

public class Solution {
    public int maxProduct(String[] words) {
        int max = 0;


        int[] masks = new int[words.length]; // alphabet masks

        for(int i = 0; i < masks.length; i++){
            for(char c: words[i].toCharArray()){
                masks[i] |= 1 << (c - ‘a‘);
            }
        }
    
        for(int i = 0; i < masks.length; i++){
            for(int j = i + 1; j < masks.length; j++){
                if((masks[i] & masks[j]) == 0){
                    max = Math.max(max, words[i].length() * words[j].length());
                }
            }
        }

        return max;
    }
}

reference：

https://discuss.leetcode.com/topic/31769/32ms-java-ac-solution/17

*Maximum Product of Word Lengths

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原文地址：http://www.cnblogs.com/hygeia/p/5775278.html