标签：
?Given? an ?arbitrary? ransom? note? string ?and ?another ?string ?containing ?letters from? all ?the ?magazines,? write ?a ?function ?that ?will ?return ?true ?if ?the ?ransom ? note ?can ?be ?constructed ?from ?the ?magazines ; ?otherwise, ?it ?will ?return ?false. ??
Each ?letter? in? the? magazine ?string ?can? only ?be? used ?once? in? your ?ransom? note.
Note:
You may assume that both strings contain only lowercase letters.
canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true
代码如下：
1 public class Solution { 2 public boolean canConstruct(String ransomNote, String magazine) { 3 if(ransomNote.length()<=magazine.length()) 4 { 5 int i=0; 6 while(i<ransomNote.length()) 7 { 8 int index=magazine.indexOf(ransomNote.charAt(i)); 9 if(index!=-1) 10 { 11 magazine= magazine.replaceFirst(magazine.substring(index,index+1),""); 12 i++; 13 } 14 else return false; 15 } 16 } 17 else return false; 18 19 return true; 20 } 21 }
标签：
原文地址：http://www.cnblogs.com/ghuosaao/p/5777591.html
