#include <iostream>
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <cmath>
#include <vector>
#include <queue>
#include <map>
#include <algorithm>
#include <set>
#define MM(a,b) memset(a,b,sizeof(a))
typedef long long ll;
typedef unsigned long long ULL;
const double eps = 1e-8;
const int inf = 0x3f3f3f3f;
const double pi=acos(-1);
using namespace std;
const int N=1e5+8;

struct Point{
   ll x,y,z,dis;
   int id;
   void read(){
       scanf("%lld%lld%lld",&x,&y,&z);
   }
   bool operator<(const Point &a) const{
       return this->dis<a.dis;
   }
}p[205],v[205];

Point operator-(Point a,Point b)
{
   return (Point){a.x-b.x,a.y-b.y,a.z-b.z};
}

double dis(Point a)
{
    return a.x*a.x+a.y*a.y+a.z*a.z;
}

Point cross(Point a,Point b)
{
   return (Point){a.y*b.z-a.z*b.y,a.z*b.x-a.x*b.z,a.x*b.y-a.y*b.x};
}

double area(Point a,Point b,Point c)
{
    return dis(cross(b-a,c-a));
}

double dot(Point a,Point b)
{
    return a.x*b.x+a.y*b.y+a.z*b.z;
}

bool onface(Point a,Point b,Point c,Point d)
{
    Point f=cross(a-b,c-b);
    return dot(f,d-b)==0;
}

int main()
{
    int cas,n,kk=0,x,y;
    scanf("%d",&cas);
    while(cas--)
    {
        scanf("%d",&n);
        for(int i=1;i<=n;i++)   p[i].read();
        ll ans6=0,ans45=0;
        for(int i=1;i<=n;i++)
           for(int j=i+1;j<=n;j++)
           {
               ll len=dis(p[i]-p[j]);
               int cnt=0;
               for(int k=1;k<=n;k++)
               if(k!=i&&k!=j)
               {
                 if(dis(p[k]-p[i])-dis(p[k]-p[j])==0)
                   {
                       v[++cnt]=p[k];
                       v[cnt].dis=dis(p[k]-p[i]);
                   }
               }
               for(int k=1;k<=cnt;k++)
                  for(int w=k+1;w<=cnt;w++)
                 {
                     if((v[w].dis-v[k].dis)!=0) continue;
                     if(onface(p[i],p[j],v[k],v[w])) continue;
                     ll tmp=dis(v[w]-v[k]);

                     if((tmp-len)==0&&(len-v[k].dis)==0) ans6++;
                     else   ans45++;
                 }
           }
        ans45/=2;ans6/=6;
        printf("Case #%d: %lld\n",++kk,ans45+ans6);
    }
    return 0;
}