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Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.
For example, given the following triangle
[
[2],
[3,4],
[6,5,7],
[4,1,8,3]
]
The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11).
public class Solution { public int minimumTotal(List<List<Integer>> triangle) { if (triangle == null || triangle.size() == 0) { return 0; } int n = triangle.size(); int[][] dp = new int[n][n]; for (int i = 0; i < n; i++) { dp[n - 1][i] = triangle.get(n-1).get(i); } for (int i = n - 2; i >= 0; i--) { for (int j = 0; j < triangle.get(i).size(); j++) { dp[i][j] = Math.min(dp[i + 1][j], dp[i + 1][j + 1]) + triangle.get(i).get(j); } } return dp[0][0]; } }
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原文地址：http://www.cnblogs.com/iwangzheng/p/5785191.html
