标签：leetcode
Follow up for "Search in Rotated Sorted Array":
What if duplicates are allowed?
Would this affect the run-time complexity? How and why?
Write a function to determine if a given target is in the array.
原题链接：https://oj.leetcode.com/problems/search-in-rotated-sorted-array-ii/题目：继续之前的题，在旋转过的有序数组中找目标值。若允许有重复的值呢？
public boolean search(int[] A, int target) {
int low = 0, high = A.length - 1;
while (low <= high) {
int mid = (low + high) / 2;
if (target == A[mid])
return true;
if (A[mid] > A[low]) {
if (target >= A[low] && target <= A[mid])
high = mid - 1;
else
low = mid + 1;
} else if (A[mid] < A[low]) {
if (target >= A[mid] && target <= A[high])
low = mid + 1;
else
high = mid - 1;
} else
low += 1;
}
return false;
}
LeetCode——Search in Rotated Sorted Array II,布布扣,bubuko.com
LeetCode——Search in Rotated Sorted Array II
标签：leetcode
原文地址：http://blog.csdn.net/laozhaokun/article/details/38454343
