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3 4 1 2 3 4 0 0 0 0 4 3 2 1 4 1 1 3 4 1 1 2 4 1 1 3 3 2 1 2 4 3 4 0 1 4 3 0 2 4 1 0 0 0 0 2 1 1 2 4 1 3 2 3 0 0
YES NO NO NO NO YES
搜索,也可以用枚举
1 //2016.8.20 2 #include<iostream> 3 #include<cstdio> 4 #include<cstring> 5 6 using namespace std; 7 8 int mp[1005][1005], book[1005][1005]; 9 int dx[4] = {0, 1, 0, -1}; 10 int dy[4] = {1, 0, -1, 0}; 11 int n, m, x2, y2; 12 bool ok, fg; 13 14 void dfs(int x, int y, int pd, int tt)//pd表示上一次的方向,tt表示转折的次数 15 { 16 if(tt>3)return ; 17 if(x == x2 && y == y2) 18 { 19 cout << "YES" << endl; 20 ok = true; 21 return ; 22 } 23 if(x<1||x>n||y<1||y>m||mp[x][y]!=0)return; 24 if(ok)return ; 25 book[x][y] = 1; 26 for(int i= 0; i < 4; i++) 27 { 28 int nx = x+dx[i]; 29 int ny = y+dy[i]; 30 if(book[nx][ny]==1)continue; 31 if(i != pd) 32 dfs(nx, ny, i, tt+1); 33 else 34 dfs(nx, ny, i, tt); 35 book[nx][ny] = 0; 36 } 37 } 38 int main() 39 { 40 int q, x1, y1; 41 while(cin>>n>>m) 42 { 43 if(n==0&&m==0)break; 44 for(int i = 1; i <= n; i++) 45 for(int j = 1; j <= m; j++) 46 scanf("%d", &mp[i][j]); 47 48 cin >> q; 49 while(q--) 50 { 51 scanf("%d%d%d%d", &x1, &y1, &x2, &y2); 52 memset(book, 0, sizeof(book)); 53 if(mp[x1][y1]==mp[x2][y2]&&mp[x1][y1]&&mp[x2][y2]&&x1>=1&&y1>=1&&x1<=n&&y1<=m&&x2>=1&&y2>=1&&x2<=n&&y2<=m)//剪枝 54 { 55 ok = false; 56 int tmp = mp[x1][y1]; 57 mp[x1][y1] = 0; 58 dfs(x1, y1, -1, 0); 59 mp[x1][y1] = tmp; 60 if(!ok)cout << "NO" << endl; 61 }else 62 { 63 cout << "NO" <<endl; 64 } 65 } 66 } 67 68 return 0; 69 }
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原文地址:http://www.cnblogs.com/Penn000/p/5791280.html