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(LeetCode)Valid Sudoku --- 合法数独

时间:2016-08-23 13:25:12      阅读:125      评论:0      收藏:0      [点我收藏+]

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Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.

The Sudoku board could be partially filled, where empty cells are filled with the character ‘.‘.

技术分享

A partially filled sudoku which is valid.

Note:
A valid Sudoku board (partially filled) is not necessarily solvable. Only the filled cells need to be validated.

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解题分析:

此题目的意思是判断给出的数独是否是合法的,那么根据题意,可以分成三步1、判断每一列是不是对的,判断每一行是不是对的,

判断九宫格是不是对的,

三个判断模块解决问题



# -*- coding:utf-8 -*-
__author__ = 'jiuzhang'
class Solution(object):
    def isValidSudoku(self, board):
        #列判断
        i = 0
        while i < 9:
            j = 0
            d = {}
            while j < 9:
                if board[i][j] != '.' and board[i][j] in d:
                    return False
                else:
                    d[board[i][j]] = True
                j += 1
            i += 1

        # 行判断
        j = 0
        while j < 9:
            i = 0
            d = {}
            while i < 9:
                if board[i][j] != '.' and board[i][j] in d:
                    return False
                else:
                    d[board[i][j]] = True
                i += 1
            j += 1
        #九宫格判断
        i = 0
        while i < 9:
            j = 0
            while j < 9:
                m = 0
                d = {}
                while m < 3:
                    n = 0
                    while n < 3:
                        if board[i + m][j + n] != '.' and board[i + m][j + n] in d:
                            return False
                        else:
                            d[board[i + m][j + n]] = True
                        n += 1
                    m += 1
                j += 3
            i += 3
        return True













(LeetCode)Valid Sudoku --- 合法数独

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原文地址:http://blog.csdn.net/u012965373/article/details/52288467

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