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题目地址:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=4705思路:若有解,两点连线最小距离=曼哈顿距离+1,则ans=abs(x1-x2)+abs(y1-y2)+abs(x3-x4)+abs(y3-y4)+2。若无解,则两线相交:对于边界,逆时针遍历,若1212或2121则此时无解,其他情况有解。注意所有点在同一行或同一列特判:+2(1 2 2 1)或不加(1 1 2 2)。
#include<queue> #include<vector> #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> using namespace std; struct point { int x, y; }; int n; const int maxn=20000+10; char ch[11][11]; int res[10]; int main() { int t; scanf("%d",&t); while(t--) { memset(ch, 0, sizeof(ch)); memset(res, 0,sizeof(res)); scanf("%d",&n); getchar(); point a1,a2,b1,b2; bool flag1 = false, flag2 = false; for(int i = 0; i < n; i++) { for(int j = 0; j < n; j++) { scanf("%c",&ch[i][j]); if(ch[i][j] == '1' && !flag1) a1.x = i, a1.y = j, flag1 = true; else if(ch[i][j] == '1') a2.x = i, a2.y = j; if(ch[i][j] == '2' && !flag2) b1.x = i, b1.y = j, flag2 = true; else if(ch[i][j] == '2') b2.x = i, b2.y = j; } getchar(); } // cout << "******************\n"; // for(int i = 0; i < n; i++) // { // for(int j = 0; j < n; j++) // printf("%c",ch[i][j]); // printf("\n"); // } // cout << "******************\n"; // cout << a1.x << " " << a1.y << "****" << a2.x << " " << a2.y << endl; // cout << b1.x << " " << b1.y << "****" << b2.x << " " << b2.y << endl; int cur = 0; for(int i = 0; i < n; i++) if(ch[i][0] != '.') res[cur++] = ch[i][0] - '0'; for(int i = 1; i < n; i++) if(ch[n - 1][i] != '.') res[cur++] = ch[n - 1][i] - '0'; for(int i = n - 2; i >= 0; i--) if(ch[i][n - 1] != '.') res[cur++] = ch[i][n - 1] - '0'; for(int i = n - 2; i >= 1; i--) if(ch[0][i] != '.') res[cur++] = ch[0][i] - '0'; bool ok = true; // cout << cur << endl; // cout << res[0] << " " << res[1] << " " << res[2] << " " << res[3] << endl; if(res[0] == 1 && res[1] == 2 && res[2] == 1 && res[3] == 2) ok = false; else if(res[0] == 2 && res[1] == 1 && res[2] == 2 && res[3] == 1) ok = false; if(!ok) { printf("-1\n"); continue; } int ans = 0; ok = false; ans += abs(a1.x - a2.x) + abs(a1.y - a2.y) + 1; ans += abs(b1.x - b2.x) + abs(b1.y - b2.y) + 1; if(a1.x == a2.x && a2.x == b1.x && b1.x == b2.x) { if(a1.y > a2.y) { point tmp = a1; a1 = a2; a2 = tmp; } if(b1.y > b2.y) { point tmp = b1; b1 = b2; b2 = tmp; } if(!(a2.y < b1.y || b2.y < a1.y)) ok = true; } else if(a1.y == a2.y && a2.y == b1.y && b1.y == b2.y) { if(a1.x > a2.x) { point tmp = a1; a1 = a2; a2 = tmp; } if(b1.x > b2.x) { point tmp = b1; b1 = b2; b2 = tmp; } if(!(a2.x < b1.x || b2.x < a1.x)) ok = true; } if(ok) ans += 2; printf("%d\n",ans); } }
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原文地址:http://blog.csdn.net/wang2147483647/article/details/52294937