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题目链接:https://uva.onlinejudge.org/external/128/12821.pdf
比赛的时候,准备用最短路来做,存两张图,做两次最短路,本来还觉得第二张图的设计很好的,很不错,结果过了好多案例,还是莫名其妙的WA了。
完了之后,听阳哥说,直接MCMF啊,当时我就傻逼了,主要是我MCMF的题目做少了,不会想到是MCMF。
这里: 每条边的容量是1,花费是边权,然后是超级源点和汇点,容量是2,花费是0。
模板来自刘汝佳,改了Bellman-Ford,用的是SPFA.
#include <iostream> #include <stdio.h> #include <cstring> #include <vector> #include <queue> #define INF 0x3f3f3f3f using namespace std; const int maxn = 600; struct Edge { int from,to,cap,flow,cost; Edge() {} Edge(int a,int b,int c,int d,int e):from(a),to(b),cap(c),flow(d),cost(e) {} }; struct MCMF { int n,m,s,t; vector<Edge> edges; vector<int> g[maxn]; int inq[maxn]; int d[maxn]; int p[maxn]; int a[maxn]; void init(int n) { this->n =n; for(int i=0; i<n; i++)g[i].clear(); edges.clear(); } void addedge(int from,int to,int cap,int cost) { Edge e1= Edge(from,to,cap,0,cost), e2= Edge(to,from,0,0,-cost); edges.push_back(e1); edges.push_back(e2); m=edges.size(); g[from].push_back(m-2); g[to].push_back(m-1); } bool spfa(int s,int t, int & flow,int & cost) { for(int i=0; i<n; i++) d[i]=INF; memset(inq,0,sizeof(inq)); d[s]=0; inq[s]=1; p[s]=0; a[s]=INF; queue<int>q; q.push(s); while(!q.empty()) { int u=q.front(); q.pop(); inq[u]=0; for(int i=0; i<g[u].size(); i++) { Edge & e = edges[g[u][i]]; if(e.cap>e.flow && d[e.to]>d[u]+e.cost) { d[e.to]=d[u]+e.cost; p[e.to]=g[u][i]; a[e.to]=min(a[u],e.cap-e.flow); if(!inq[e.to]) { q.push(e.to); inq[e.to]=1; } } } } if(d[t]==INF) return false; flow+=a[t]; cost+=a[t]*d[t]; for(int u=t; u!=s; u=edges[p[u]].from) { edges[p[u]].flow +=a[t]; edges[p[u]^1].flow-=a[t]; } return true; } int MincostMaxflow(int s,int t) { int flow=0,cost =0; while(spfa(s,t,flow,cost)); return cost; } } sol; int main() { freopen("input.txt","r",stdin); freopen("output.txt","w",stdout); int n,m,cas=1; while(scanf("%d%d",&n,&m)!=EOF) { int s=0,t=n+1; sol.init(n+2); while(m--) { int u,v,c,ad; scanf("%d%d%d%d",&u,&v,&c,&ad); sol.addedge(u,v,1,c); sol.addedge(u,v,1,c+ad); } sol.addedge(s,1,2,0); sol.addedge(n,t,2,0); printf("Case %d: %d\n",cas++,sol.MincostMaxflow(s,t)); } }
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原文地址:http://www.cnblogs.com/TreeDream/p/5801286.html